Model 4 Time & Distance With Ratios Practice Questions Answers Test With Solutions & More Shortcuts
TIME & DISTANCE PRACTICE TEST [5 - EXERCISES]
Model 1 Basic Time & Distance Using Formula
Model 2 Vehicles In X/y Of Its Usual Speed
Model 3 Problems On Average Speed
Model 4 Time & Distance With Ratios
Model 5 Problems With Races
Question : 11 [SSC CGL Prelim 2008]
Two trains started at the same time, one from A to B and the other from B to A. If they arrived at B and A respectively 4 hours and 9 hours after they passed each other, the ratio of the speed of the two trains was
a) 3 : 2
b) 4 : 3
c) 5 : 4
d) 2 : 1
Answer »Answer: (a)
Using Rule 11,Time taken by 1st man to reach B after meeting 2nd man at C is '$t_1$' and time taken by 2nd man to reach A after meeting 1st man at C is '$t_2$' then:${\text"Speed of 1st man"(s_1)}/{\text"Speed of 2nd man"(s_2)} = √{t_2/t_1}$Distance from A to B = $s_1t_1 + S_2t_2$
Required ratio of the speed of two trains
= $√{9}/√{4} = 3/2$ or 3 : 2
Question : 12 [SSC CGL Tier-I 2016]
A car travels 80 km. in 2 hours and a train travels 180 km. in 3 hours. The ratio of the speed of the car to that of the train is :
a) 3 : 2
b) 3 : 4
c) 4 : 3
d) 2 : 3
Answer »Answer: (d)
Speed = $\text"Distance"/ \text"Time"$
∴ Speed of car : Speed of train
= $80/2 : 180/3$ = 40 : 60 = 2 : 3
Question : 13 [SSC CGL Tier-I 2014]
It takes 8 hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the car is
a) 3 : 2
b) 3 : 4
c) 4 : 3
d) 2 : 3
Answer »Answer: (b)
Using Rule 1,
Speed of train = x kmph
Speed of car = y kmph
Case I,
$120/x + {600 - 120}/y$ = 8
$120/x + 480/y$ = 8
$15/x + 60/y$ = 1 ...(i)
Case II,
$200/x + 400/y$ = 8 hours 20 minutes
$200/x + 400/y = 8{1}/3$ hours = $25/3$
$8/x + 16/y = 1/3$
$24/x + 48/y$ = 1 ...(ii)
$15/x + 60/y = 24/x + 48/y$
$24/x - 15/x = 60/y - 48/y$
$9/x = 12/y$
$x/y = 9/12 = 3/4$ = 3 : 4
Question : 14 [SSC MTS 2017]
The speeds of three cars are in the ratio of 1 : 3 : 5. The ratio among the time taken by these cars to travel the same distance is
a) 15 : 3 : 5
b) 15 : 5 : 3
c) 5 : 3 : 1
d) 3 : 5 : 15
Answer »Answer: (d)
Speed ∝ $1/\text"Time"$
Required ratio of time
= $1 : 1/3 : 1/5$
= 15 : $1/3 × 15 : 1/5 × 15$
= 15 : 5 : 3
Question : 15 [SSC CGL Prelim 2004]
A truck covers a distance of 550 metres in 1 minute whereas a bus covers a distance of 33 kms in 45 minutes. The ratio of their speed is :
a) 3 : 5
b) 3 : 4
c) 50 : 3
d) 4 : 3
Answer »Answer: (b)
Using Rule 1,
Speed of truck = 550m/minute
Speed of bus = $33000/45$ m/minute
or $2200/3$ m/minute
Required ratio = 550 : $2200/3$
= $1 : 4/3 = 3 : 4$
IMPORTANT QUANTITATIVE APTITUDE EXERCISES
Model 4 Time & Distance With Ratios Shortcuts »
Click to Read...Model 4 Time & Distance With Ratios Online Quiz
Click to Start..TIME & DISTANCE SHORTCUTS AND TECHNIQUES WITH EXAMPLES
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Model 1 Basic Time & Distance Using Formula
Defination & Shortcuts … -
Model 2 Vehicles In X/y Of Its Usual Speed
Defination & Shortcuts … -
Model 3 Problems On Average Speed
Defination & Shortcuts … -
Model 4 Time & Distance With Ratios
Defination & Shortcuts … -
Model 5 Problems With Races
Defination & Shortcuts …
QUANTITATIVE APTITUDE CATEGORIES
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» Number System
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» Average
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» LCM & HCF
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» Percentage
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» Profit & Loss
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» Time & Work
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» Pipes & Cisterns
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» Time & Distance
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» Trains
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» Compound Interest
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» Simplification
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» Discount
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» Power
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» Permutations & Combination
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» Ratio & Proportion
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» Advance Math
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» Algebraic Expressions
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» Trigonometric Ratios & Identities
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» Simple Interest
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» Alligation & Mixtures
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» Boats & Streams
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» Set Theory
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» Linear Equations
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» Quadratic Equations
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» Mensuration
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» Squareroots & Cuberoots
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» Data Sufficiency
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» Logarithm
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» Probability
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» Statistics
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